求指点 步进电机 问题
本帖最后由 DebugLab 于 2024-11-15 15:48 编辑用 AI8G1K08-20P,ULN2003A ,驱动 28BYJ-48歨进电机的电路是不是有问题，上电没反应，断开P30就可以正常上电。
但是上电后启动M3步进电机时，电机一直在振动，要帮它扭一扭转轴才能转起来，
我在KEIL里手动仿真，发现在第一次循环到 case 3 结束之后会异常 跳转到扫描按键的中断里面去，之后就能正常循环
if (ucKeySec == 1)
{
switch(num2)
{
case 0:M3A = 1;M3B = 0;M3C = 0;M3D = 0;break;
case 1:M3A = 1;M3B = 1;M3C = 0;M3D = 0;break;
case 2:M3A = 0;M3B = 1;M3C = 0;M3D = 0;break;
case 3:M3A = 0;M3B = 1;M3C = 1;M3D = 0;break;
case 4:M3A = 0;M3B = 0;M3C = 1;M3D = 0;break;
case 5:M3A = 0;M3B = 0;M3C = 1;M3D = 1;break;
case 6:M3A = 0;M3B = 0;M3C = 0;M3D = 1;break;
case 7:M3A = 1;M3B = 0;M3C = 0;M3D = 1;break;
}
delay1m(3);
num2++;
if(num2 == 8)num2 = 0;
}
if (Ir2_time == 1)
{
ucKeySec = 0;
sec_flag = 1;
if (sec_cnt == 3)
{
static int cyc1 = 1529;
sec_cnt = 0;
sec_flag = 0;
while (cyc1--)
{
switch(num1)
{
case 0:M2A = 1;M2B = 0;M2C = 0;M2D = 0;break;
case 1:M2A = 1;M2B = 1;M2C = 0;M2D = 0;break;
case 2:M2A = 0;M2B = 1;M2C = 0;M2D = 0;break;
case 3:M2A = 0;M2B = 1;M2C = 1;M2D = 0;break; //这里,在弟一次运行到这行结束后会跳转到按键扫描中断里，第2次及以后就可正常循环到 case 4
case 4:M2A = 0;M2B = 0;M2C = 1;M2D = 0;break;
case 5:M2A = 0;M2B = 0;M2C = 1;M2D = 1;break;
case 6:M2A = 0;M2B = 0;M2C = 0;M2D = 1;break;
case 7:M2A = 1;M2B = 0;M2C = 0;M2D = 1;break;
}
delay1m(3);
//num1++;
if(++num1 == 8)num1 = 0;
}
Ir2_time = 0;
ucKeySec = 1;
}
}
}
void TM0_Isr() interrupt 1
{
TF0 = 0;/*清除中断标志*/
TR0 = 0;/*关中断*/
/*扫描按键*/
Key_Scan();
TL0 = 0xCD; //设置定时初值
TH0 = 0xD4; //设置定时初值
TR0 = 1; /*开中断*/
}
截图202411151348026273.jpg (97.55 KB, 下载次数: 0)
截图202411151348026273.jpg 检查P31、P32状态，是不是都为0，是不是进入了软件模拟USB下载状态
步进电机速度过快是无法启动的，只会振动
定时器中断可以打断主程序，是正常的
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